Swift 2.0 - Binary Operator "|" cannot be applied to two UIUserNotificationType operands

Nikita Zernov picture Nikita Zernov · Jun 10, 2015 · Viewed 46.9k times · Source

I am trying to register my application for local notifications this way:

UIApplication.sharedApplication().registerUserNotificationSettings(UIUserNotificationSettings(forTypes: UIUserNotificationType.Alert | UIUserNotificationType.Badge, categories: nil))

In Xcode 7 and Swift 2.0 - I get error Binary Operator "|" cannot be applied to two UIUserNotificationType operands. Please help me.

Answer

Mick MacCallum picture Mick MacCallum · Jun 10, 2015

In Swift 2, many types that you would typically do this for have been updated to conform to the OptionSetType protocol. This allows for array like syntax for usage, and In your case, you can use the following.

let settings = UIUserNotificationSettings(forTypes: [.Alert, .Badge], categories: nil)
UIApplication.sharedApplication().registerUserNotificationSettings(settings)

And on a related note, if you want to check if an option set contains a specific option, you no longer need to use bitwise AND and a nil check. You can simply ask the option set if it contains a specific value in the same way that you would check if an array contained a value.

let settings = UIUserNotificationSettings(forTypes: [.Alert, .Badge], categories: nil)

if settings.types.contains(.Alert) {
    // stuff
}

In Swift 3, the samples must be written as follows:

let settings = UIUserNotificationSettings(types: [.alert, .badge], categories: nil)
UIApplication.shared.registerUserNotificationSettings(settings)

and

let settings = UIUserNotificationSettings(types: [.alert, .badge], categories: nil)

if settings.types.contains(.alert) {
    // stuff
}