I am trying to send a "Class" to my Watchkit extension but I get this error.
* Terminating app due to uncaught exception 'NSInvalidUnarchiveOperationException', reason: '* -[NSKeyedUnarchiver decodeObjectForKey:]: cannot decode object of class (MyApp.Person)
Archiving and unarchiving works fine on the iOS App but not while communicating with the watchkit extension. What's wrong?
InterfaceController.swift
let userInfo = ["method":"getData"]
WKInterfaceController.openParentApplication(userInfo,
reply: { (userInfo:[NSObject : AnyObject]!, error: NSError!) -> Void in
println(userInfo["data"]) // prints <62706c69 7374303...
if let data = userInfo["data"] as? NSData {
if let person = NSKeyedUnarchiver.unarchiveObjectWithData(data) as? Person {
println(person.name)
}
}
})
AppDelegate.swift
func application(application: UIApplication!, handleWatchKitExtensionRequest userInfo: [NSObject : AnyObject]!,
reply: (([NSObject : AnyObject]!) -> Void)!) {
var bob = Person()
bob.name = "Bob"
bob.age = 25
reply(["data" : NSKeyedArchiver.archivedDataWithRootObject(bob)])
return
}
Person.swift
class Person : NSObject, NSCoding {
var name: String!
var age: Int!
// MARK: NSCoding
required convenience init(coder decoder: NSCoder) {
self.init()
self.name = decoder.decodeObjectForKey("name") as! String?
self.age = decoder.decodeIntegerForKey("age")
}
func encodeWithCoder(coder: NSCoder) {
coder.encodeObject(self.name, forKey: "name")
coder.encodeInt(Int32(self.age), forKey: "age")
}
}
According to Interacting with Objective-C APIs:
When you use the
@objc(
name)
attribute on a Swift class, the class is made available in Objective-C without any namespacing. As a result, this attribute can also be useful when you migrate an archivable Objective-C class to Swift. Because archived objects store the name of their class in the archive, you should use the@objc(
name)
attribute to specify the same name as your Objective-C class so that older archives can be unarchived by your new Swift class.
By adding the annotation @objc(name)
, namespacing is ignored even if we are just working with Swift. Let's demonstrate. Imagine target A
defines three classes:
@objc(Adam)
class Adam:NSObject {
}
@objc class Bob:NSObject {
}
class Carol:NSObject {
}
If target B calls these classes:
print("\(Adam().classForCoder)")
print("\(Bob().classForCoder)")
print("\(Carol().classForCoder)")
The output will be:
Adam
B.Bob
B.Carol
However if target A calls these classes the result will be:
Adam
A.Bob
A.Carol
To resolve your issue, just add the @objc(name) directive:
@objc(Person)
class Person : NSObject, NSCoding {
var name: String!
var age: Int!
// MARK: NSCoding
required convenience init(coder decoder: NSCoder) {
self.init()
self.name = decoder.decodeObjectForKey("name") as! String?
self.age = decoder.decodeIntegerForKey("age")
}
func encodeWithCoder(coder: NSCoder) {
coder.encodeObject(self.name, forKey: "name")
coder.encodeInt(Int32(self.age), forKey: "age")
}
}