How to get device current orientation in an App Extension, I have tried below two methods but no success.
It always return UIDeviceOrientationUnknown
[[UIDevice currentDevice] orientation]
It shows red message that ‘sharedApplication’ is not available on iOS (App Extension)
[[UIApplication sharedApplication] statusBarOrientation];
I also add an observer but it not getting called.
[[NSNotificationCenter defaultCenter] addObserver:self.view selector:@selector(notification_OrientationWillChange:) name:UIApplicationWillChangeStatusBarOrientationNotification object:nil];
- (void)notification_OrientationWillChange:(NSNotification*)n
{
UIInterfaceOrientation orientation = (UIInterfaceOrientation)[[n.userInfo objectForKey:UIApplicationStatusBarOrientationUserInfoKey] intValue];
if (orientation == UIInterfaceOrientationLandscapeLeft)
[self.textDocumentProxy insertText:@"Left"];
if (orientation == UIInterfaceOrientationLandscapeRight)
[self.textDocumentProxy insertText:@"Right"];
}
So now how can anyone get current device orientation.
I got an idea!
extension UIScreen {
var orientation: UIInterfaceOrientation {
let point = coordinateSpace.convertPoint(CGPointZero, toCoordinateSpace: fixedCoordinateSpace)
if point == CGPointZero {
return .Portrait
} else if point.x != 0 && point.y != 0 {
return .PortraitUpsideDown
} else if point.x == 0 && point.y != 0 {
return .LandscapeLeft
} else if point.x != 0 && point.y == 0 {
return .LandscapeRight
} else {
return .Unknown
}
}
}
EDIT: On Swift 4 you can do:
extension UIScreen {
var orientation: UIInterfaceOrientation {
let point = coordinateSpace.convert(CGPoint.zero, to: fixedCoordinateSpace)
switch (point.x, point.y) {
case (0, 0):
return .portrait
case let (x, y) where x != 0 && y != 0:
return .portraitUpsideDown
case let (0, y) where y != 0:
return .landscapeLeft
case let (x, 0) where x != 0:
return .landscapeRight
default:
return .unknown
}
}
}