I'm working through the tutorial here (learning Swift) for my first app: http://www.appcoda.com/search-bar-tutorial-ios7/
I'm stuck on this part (Objective-C code):
- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{
NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"name contains[c] %@", searchText];
searchResults = [recipes filteredArrayUsingPredicate:resultPredicate];
}
Can anyone advise how to create an equivalent for NSPredicate in Swift?
This is really just a syntax switch. OK, so we have this method call:
[NSPredicate predicateWithFormat:@"name contains[c] %@", searchText];
In Swift, constructors skip the "blahWith…" part and just use the class name as a function and then go straight to the arguments, so [NSPredicate predicateWithFormat: …]
would become NSPredicate(format: …)
. (For another example, [NSArray arrayWithObject: …]
would become NSArray(object: …)
. This is a regular pattern in Swift.)
So now we just need to pass the arguments to the constructor. In Objective-C, NSString literals look like @""
, but in Swift we just use quotation marks for strings. So that gives us:
let resultPredicate = NSPredicate(format: "name contains[c] %@", searchText)
And in fact that is exactly what we need here.
(Incidentally, you'll notice some of the other answers instead use a format string like "name contains[c] \(searchText)"
. That is not correct. That uses string interpolation, which is different from predicate formatting and will generally not work for this.)