I am trying to show three buttons on one button click. Before a button click all three buttons are hidden. I set the hidden property and I am also calling a function on a button click. The problem is that when I load the page all buttons are visible. It was working perfectly before I added CSS. I don't understand where the problem is.
Here is my code:
What changes can I make, so that when I click on edit it sets the hidden
property of three buttons to false
?
It also works without jQuery if you do the following changes:
Add type="button"
to the edit button in order not to trigger submission of the form.
Change the name of your function from change()
to anything else.
Don't use hidden="hidden"
, use CSS instead: style="display: none;"
.
The following code works for me:
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="STYLESHEET" type="text/css" href="dba_style/buttons.css" />
<title>Untitled Document</title>
</head>
<script type="text/javascript">
function do_change(){
document.getElementById("save").style.display = "block";
document.getElementById("change").style.display = "block";
document.getElementById("cancel").style.display = "block";
}
</script>
<body>
<form name="form1" method="post" action="">
<div class="buttons">
<button type="button" class="regular" name="edit" id="edit" onclick="do_change(); return false;">
<img src="dba_images/textfield_key.png" alt=""/>
Edit
</button>
<button type="submit" class="positive" name="save" id="save" style="display:none;">
<img src="dba_images/apply2.png" alt=""/>
Save
</button>
<button class="regular" name="change" id="change" style="display:none;">
<img src="dba_images/textfield_key.png" alt=""/>
change
</button>
<button class="negative" name="cancel" id="cancel" style="display:none;">
<img src="dba_images/cross.png" alt=""/>
Cancel
</button>
</div>
</form>
</body>
</html>