I am trying to connect using Hibernate to a database.
this current table has the following layout:
(field1, field2, field3, optional1, optioanl2...)
where field1, field2, field3 are all foreign keys, and together make up a composite key.
I have the following classes:
@Entity
@Table(name = "db_table_mainRecords")
public class MainRecord implements Serializable{
@EmbeddedId
private MainRecordKey lqk;
@Transient
private String field1;
@Transient
private int field2;
@Transient
private int field3;
@Column(name = "optional_1")
private double optional1;
@Column(name = "optional_2")
private double optional2;
....
// Getters and setters for all fields, including fields within MainClassKey
....
}
and this accompanying it:
@Embeddable
@Table(name = "db_table_mainRecords")
public class MainRecordKey implements Serializable{
@Column(name = "field1")
private String field_1;
@Column(name = "field_2")
private int field2;
@Column(name = "field_3")
private int field3;
}
I am getting the following error:
org.hibernate.QueryException - could not resolve property: field3 of: path.MainRecord at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:67)
here is my Bo /dao code
public List<MainRecord> getMainRecords(int e){
Criterion crit1 = Restrictions.eq("field3", e);
ArrayList<MainRecord> list = (ArrayList<MainRecord>) dao.getMainRecords(crit1);
}
public List<MainRecord> getMainRecords(Criterion criteria){
if(criteria == null)
return new ArrayList<MainReocrd>();
return (List<MainRecord>) getHibernateTemplate().findByCriteria(DetachedCriteria.forClass(MainRecord.class).add(criteria));
}
Try to change all int
to Integer
and double
to Double
in your mapping files MainRecord
and MainRecordKey
.
UPDATE Try this:
Restrictions.eq("lqk.field3", e);