I'd like to do the following:
Vec
for a certain key, and store it for later use.Vec
for the key, but still keep it in the variable.How to do this efficiently? Naturally I thought I could use match
:
use std::collections::HashMap;
// This code doesn't compile.
let mut map = HashMap::new();
let key = "foo";
let values: &Vec<isize> = match map.get(key) {
Some(v) => v,
None => {
let default: Vec<isize> = Vec::new();
map.insert(key, default);
&default
}
};
When I tried it, it gave me errors like:
error[E0502]: cannot borrow `map` as mutable because it is also borrowed as immutable
--> src/main.rs:11:13
|
7 | let values: &Vec<isize> = match map.get(key) {
| --- immutable borrow occurs here
...
11 | map.insert(key, default);
| ^^^ mutable borrow occurs here
...
15 | }
| - immutable borrow ends here
I ended up with doing something like this, but I don't like the fact that it performs the lookup twice (map.contains_key
and map.get
):
// This code does compile.
let mut map = HashMap::new();
let key = "foo";
if !map.contains_key(key) {
let default: Vec<isize> = Vec::new();
map.insert(key, default);
}
let values: &Vec<isize> = match map.get(key) {
Some(v) => v,
None => {
panic!("impossiburu!");
}
};
Is there a safe way to do this with just one match
?
The entry
API is designed for this. In manual form, it might look like
use std::collections::hash_map::Entry;
let values: &Vec<isize> = match map.entry(key) {
Entry::Occupied(o) => o.into_mut(),
Entry::Vacant(v) => v.insert(default)
};
Or one can use the briefer form:
map.entry(key).or_insert_with(|| default)
If default
is OK/cheap to compute even when it isn't inserted, it can also just be:
map.entry(key).or_insert(default)