Ruby, Lua, R and Awk methods for performing a global pattern substitution.
I am trying to remove a parenthesis from a string in R and run into the following error: string <…
r string gsubI have a string variable containing alphabet[a-z], space[ ], and apostrophe['],eg. x <- "a'b c" I want …
r string gsubI'm using awk '{gsub(/^[ \t]+|[ \t]+$/,""); print;}' in.txt > out.txt to remove both leading and trailing …
awk whitespace gsub removing-whitespaceI'm trying to replace characters in a data.frame. I have a solution for this > df <- data.…
r regex gsubI am reading in a bunch of CSVs that have stuff like "sales - thousands" in the title and come …
r gsubI have this expression: channelName = rhash["Channel"].gsub("'", " ") it works fine. However, I can only substitute 1 character with it. …
ruby string gsubI would like to remove everything after a space in a string. For example: "my string is sad" should return "…
r regex gsubI have data as below, I like to replace "." with space using gsub() but I could not get correct output. …
r gsubI'm trying to figure out how to replace a quote like ' with something like \'. How would I do …
ruby string gsub