How to change the current working directory in Groovy

groovy cwd
Joe picture Joe · Aug 12, 2013 · Viewed 36.3k times · Source

Now, I am writting a Groovy script to invoke other's interface. But I need change my current working path when running the script. I know it is not possible in Java. Is it possible in Groovy?

Answer

kirill-a picture kirill-a · May 18, 2016

If you can run other script as separate process, you can give ProcessBuilder parameter working dir:

def processBuilder=new ProcessBuilder(command)
processBuilder.directory(new File("Working dir"))
def process = processBuilder.start()

or

command.execute(null, new File("Working dir"))

so that process will switch to your new folder and execute it there.

Related questions

Hibernate: Automatically creating/updating the db tables based on entity classes

I have the following entity class (in Groovy): import javax.persistence.Entity import javax.persistence.Id import javax.persistence.GeneratedValue import javax.persistence.GenerationType @Entity public class ServerNode { @Id @GeneratedValue(strategy = GenerationType.AUTO) Long id String firstName String lastName } and …

Read More
How do I get the output of a shell command executed using into a variable from Jenkinsfile (groovy)?

I have something like this on a Jenkinsfile (Groovy) and I want to record the stdout and the exit code in a variable in order to use the information later. sh "ls -l" How can I do this, especially as …

Read More
Converting a string to int in Groovy

I have a String that represents an integer value and would like to convert it to an int. Is there a groovy equivalent of Java's Integer.parseInt(String)?

Read More