I'm using Yii2 gridview widget to display the data.
I'm using two tables named as message and message_trigger.
In message table columns are object_model
, Object_id
.
In message_trigger the column are object_id
, object_name
.
The grid get the values from the table message. So grid fields are Object_model
, Object_id
.
Now my problem is I need to show Object_name
from the table message_trigger
based on the object_id
from the table message.
In my form I have used grid like this
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'object_model',
'object_id',
['class' => 'yii\grid\ActionColumn', 'template' => '{view} {update} {delete} '],
],
]); ?>
In model I have used
public function search($params){
$query = AlertTrigger::find()->where(['alert_id'=>$params['id']])->andWhere(['!=','status',2]);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
}
In Message
Model
public function getMessageTrigger()
{
return $this->hasOne(MessageTrigger::className(), ['object_id' => 'object_id']);
}
in view
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'object_model',
'object_id',
[
'label' => 'Name',
'value' => 'messageTrigger.object_name',
],
['class' => 'yii\grid\ActionColumn', 'template' => '{view} {update} {delete} '],
],
]); ?>