If T be an ordered tree with more than one node. Is it possible the pre-order traversal of T visit the nodes in the same order as the post-order traversal of T? if "yes" can you please give an example. And if "No" could you please explain why it cannot occur?
Unless I'm missing something painfully obvious, the answer would be no. A ordered tree with > 1 node (say for example, 2 nodes) will look like this.
A B
or
A C
Post-order traversal visits the nodes in the order left-right-root and pre-order visits the nodes in the order of root-left-right. In order for them to produce the same output, "left" must be equals to "root", which just doesn't make sense. With the above example, pre-order will produce AB or AC respectively and post-order will produce BA and CA.