Defining default sort-order in Grails/GORM

knorv picture knorv · Feb 6, 2009 · Viewed 22.8k times · Source

Let's say I have definied a User object using GORM. Each user can have zero or more Login:s. Each Login has a timestamp. When retrieving user.logins I want the logins to be sorted based on the value of login.date. What is the correct Grails way to achieve this?

Example: I want the following code to list all the user's logins in ascending order.

<g:each var="login" in="${user.logins}">
  <tr>
    <td>${login.date}</td>
  </tr>
</g:each>

These are the referenced classes:

class User {
  ...
  def hasMany = [logins: Login]
  static fetchMode = [logins: "eager"]
}

class Login {
  Date date
  ...
  def belongsTo = [User]
}

I'm running Grails 1.0.4 which is the latest stable release.

Answer

user113443 picture user113443 · May 28, 2009

They show how to do this on the GORM page in the reference guide (section 5). The bit you want is near the bottom of that document is the section you want. They have two simple examples:

class Airport {
    …
    static mapping = {
        sort "name"
    }
}

class Airport {
    …
    static mapping = {
        sort name:"desc"
    }
}

They also have an example of sorting on an association:

class Airport {
    …
    static hasMany = [flights:Flight]
    static mapping = {
        flights sort:'number'
    }
}