I'm writing a program in Go that executes a server like program (also Go). Now I want to have the stdout of the child program in my terminal window where I started the parent program. One way to do this is with the cmd.Output()
function, but this prints the stdout only after the process has exited. (That's a problem because this server-like program runs for a long time and I want to read the log output)
The variable out
is of type io.ReadCloser
and I don't know what I should do with it to achieve my task, and I can't find anything helpful on the web on this topic.
func main() {
cmd := exec.Command("/path/to/my/child/program")
out, err := cmd.StdoutPipe()
if err != nil {
fmt.Println(err)
}
err = cmd.Start()
if err != nil {
fmt.Println(err)
}
//fmt.Println(out)
cmd.Wait()
}
Explanation to the code: uncomment the Println
function to get the code to compile, I know that Println(out io.ReadCloser)
is not a meaningful function.
(it produces the output &{3 |0 <nil> 0}
) These two lines are just required to get the code to compile.
Now I want to have the stdout of the child program in my terminal window where I started the parent program.
No need to mess with pipes or goroutines, this one is easy.
func main() {
// Replace `ls` (and its arguments) with something more interesting
cmd := exec.Command("ls", "-l")
cmd.Stdout = os.Stdout
cmd.Stderr = os.Stderr
cmd.Run()
}