Format a float to n decimal places and no trailing zeros

Question

I want to display a float with the entire integer part and up to two decimals for the fractional part, without trailing zeros.

http://play.golang.org/p/mAdQl6erWX:

// Desired output: 
// "1.9"
// "10.9"
// "100.9"

fmt.Println("2g:")
fmt.Println(fmt.Sprintf("%.2g", 1.900)) // outputs "1.9"
fmt.Println(fmt.Sprintf("%.2g", 10.900)) // outputs "11"
fmt.Println(fmt.Sprintf("%.2g", 100.900)) // outputs "1e+02"

fmt.Println("\n2f:")
fmt.Println(fmt.Sprintf("%.2f", 1.900)) // outputs "1.90"
fmt.Println(fmt.Sprintf("%.2f", 10.900)) // outputs "10.90"
fmt.Println(fmt.Sprintf("%.2f", 100.900)) // outputs "100.90"

Formatting with 2g has the problem that it starts rounding when the integer increases order of magnitudes. Also, it sometimes displays numbers with an e.

Formatting with 2f has the problem that it will display trailing zeros. I could write a post-processing function that removes trailing zeros, but I rather do this with Sprintf.

Can this be done in a generic way using Sprintf?
If not, what's a good way to do this?

Answer 1

strconv.FormatFloat(10.900, 'f', -1, 64)

This will result in 10.9.

The -1 as the third parameter tells the function to print the fewest digits necessary to accurately represent the float.

See here: https://golang.org/pkg/strconv/#FormatFloat