Filter object properties by key in ES6

29er picture 29er · Aug 3, 2016 · Viewed 344.8k times · Source

Let's say I have an object:

{
  item1: { key: 'sdfd', value:'sdfd' },
  item2: { key: 'sdfd', value:'sdfd' },
  item3: { key: 'sdfd', value:'sdfd' }
}

I want to create another object by filtering the object above so I have something like.

 {
    item1: { key: 'sdfd', value:'sdfd' },
    item3: { key: 'sdfd', value:'sdfd' }
 }

I am looking for a clean way to accomplish this using Es6, so spread operators are available to me.

Answer

ssube picture ssube · Aug 3, 2016

If you have a list of allowed values, you can easily retain them in an object using:

const raw = {
  item1: { key: 'sdfd', value:'sdfd' },
  item2: { key: 'sdfd', value:'sdfd' },
  item3: { key: 'sdfd', value:'sdfd' }
};

const allowed = ['item1', 'item3'];

const filtered = Object.keys(raw)
  .filter(key => allowed.includes(key))
  .reduce((obj, key) => {
    obj[key] = raw[key];
    return obj;
  }, {});

console.log(filtered);

This uses:

  1. Object.keys to list all properties in raw (the original data), then
  2. Array.prototype.filter to select keys that are present in the allowed list, using
    1. Array.prototype.includes to make sure they are present
  3. Array.prototype.reduce to build a new object with only the allowed properties.

This will make a shallow copy with the allowed properties (but won't copy the properties themselves).

You can also use the object spread operator to create a series of objects without mutating them (thanks to rjerue for mentioning this):

const raw = {
  item1: { key: 'sdfd', value:'sdfd' },
  item2: { key: 'sdfd', value:'sdfd' },
  item3: { key: 'sdfd', value:'sdfd' }
};

const allowed = ['item1', 'item3'];

const filtered = Object.keys(raw)
  .filter(key => allowed.includes(key))
  .reduce((obj, key) => {
    return {
      ...obj,
      [key]: raw[key]
    };
  }, {});

console.log(filtered);

For purposes of trivia, if you wanted to remove the unwanted fields from the original data (which I would not recommend doing, since it involves some ugly mutations), you could invert the includes check like so:

const raw = {
  item1: { key: 'sdfd', value:'sdfd' },
  item2: { key: 'sdfd', value:'sdfd' },
  item3: { key: 'sdfd', value:'sdfd' }
};

const allowed = ['item1', 'item3'];

Object.keys(raw)
  .filter(key => !allowed.includes(key))
  .forEach(key => delete raw[key]);

console.log(raw);

I'm including this example to show a mutation-based solution, but I don't suggest using it.