I have a target file path that is structured like example below.
C:\Program Files\Test\foobar.exe /G
What I need to do is be able to execute this file using VBA's shell()
command.
How do I have to format the file path to tell Shell()
that there is an argument that it needs to call along with running the .exe
What I've read/tried (with no avail) is below with the results to the right.
file = """C:\Program Files\Test\foobar.exe"" /G" <---Bad file name or number (Error 52)
shell(file)
file2 = "C:\Program Files\Test\foobar.exe /G" <---file never found
shell(file2)
I've succeeded with running other .exe's using shell() so I know it's not a problem with VBA or the function.
Example:
works = "C:\Program Files\Test\test.exe"
shell(works)
I'm not particularly familiar with the process involved with executing files that require additional parameters so if I misspeak or you need more information, please let me know.
This works for me (Excel 2013):
Public Sub StartExeWithArgument()
Dim strProgramName As String
Dim strArgument As String
strProgramName = "C:\Program Files\Test\foobar.exe"
strArgument = "/G"
Call Shell("""" & strProgramName & """ """ & strArgument & """", vbNormalFocus)
End Sub
With inspiration from here https://stackoverflow.com/a/3448682.