How can I make default value for a field to be taken from existing objects of a model?
I tried these and it didn't worked:
1)
class ModelA(models.Model):
fieldA = models.CharField(default=self.get_previous())
def get_previous(self):
return ModelA.objects.all()[0].fieldA
NameError: name 'self' is not defined
2)
class ModelA(models.Model):
fieldA = models.CharField(default=ModelA.get_previous())
@staticmethod
def get_previous():
return ModelA.objects.all()[0].fieldA
NameError: name 'ModelA' is not defined
3)
class ModelA(models.Model):
fieldA = models.CharField(default=get_previous())
def get_previous():
return ModelA.objects.all()[0].fieldA
NameError: global name 'get_previous' is not defined
4)
def get_previous():
return ModelA.objects.all()[0].fieldA
class ModelA(models.Model):
fieldA = models.CharField(default=get_previous())
NameError: global name 'ModelA' is not defined
I it's clear why 3) and 4) won't work. I can imagine why 1) won't work - looks like class' properies can't refer to instance's (i.e. self). I can imagine why 2) won't work - apparently there's no reference to ModelA until interpreter will go trough whole class.
So how should I approach this?
In your examples, you need to remove the call operator ()
.
Currently the statement is executed immediately at the first read-parsing cycle. By specifying the symbol name instead, the Django class receives a function pointer which it will execute when it actually needs the default value.
The example becomes:
def get_previous():
return ModelA.objects.all()[0].fieldA
class ModelA(models.Model):
fieldA = models.CharField(default=get_previous)
If you're going to do this for a lot of fields, consider overridding the save
function, so you only have to fetch the previous object from the database just once.