Delphi used: 2007.
Hello,
I have a simple web page with two text input and one file input. Now, for the form to be sent, both the text inputs and the file input have to be filled. With Synapse, I know how to upload a file (HttpPostFile) and how to post data (HttpMethod). However, I don't know how to do both.
After looking at the source code of Synapse, I guess I have to "format" my data with boundaries or something like that. I guess I should have one boundary for my input file and another boundary for my text inputs. I found an article on the subject, but it's about sending email attachments. I tried to reproduce what they said with Synapse, with no results.
Code for HttpPostFile:
function HttpPostFile(const URL, FieldName, FileName: string;
const Data: TStream; const ResultData: TStrings): Boolean;
var
HTTP: THTTPSend;
Bound, s: string;
begin
Bound := IntToHex(Random(MaxInt), 8) + '_Synapse_boundary';
HTTP := THTTPSend.Create;
try
s := '--' + Bound + CRLF;
s := s + 'content-disposition: form-data; name="' + FieldName + '";';
s := s + ' filename="' + FileName +'"' + CRLF;
s := s + 'Content-Type: Application/octet-string' + CRLF + CRLF;
WriteStrToStream(HTTP.Document, s);
HTTP.Document.CopyFrom(Data, 0);
s := CRLF + '--' + Bound + '--' + CRLF;
WriteStrToStream(HTTP.Document, s);
HTTP.MimeType := 'multipart/form-data; boundary=' + Bound;
Result := HTTP.HTTPMethod('POST', URL);
if Result then
ResultData.LoadFromStream(HTTP.Document);
finally
HTTP.Free;
end;
end;
Thank you.
Your code is close. You are only sending your file field but not your text fields. To do all three, try this instead:
function HttpPostFile(const URL, InputText1FieldName, InputText1, InputText2FieldName, InputText2, InputFileFieldName, InputFileName: string; InputFileData: TStream; ResultData: TStrings): Boolean;
var
HTTP: THTTPSend;
Bound: string;
begin
Bound := IntToHex(Random(MaxInt), 8) + '_Synapse_boundary';
HTTP := THTTPSend.Create;
try
WriteStrToStream(HTTP.Document,
'--' + Bound + CRLF +
'Content-Disposition: form-data; name=' + AnsiQuotedStr(InputText1FieldName, '"') + CRLF +
'Content-Type: text/plain' + CRLF +
CRLF);
WriteStrToStream(HTTP.Document, InputText1);
WriteStrToStream(HTTP.Document,
CRLF +
'--' + Bound + CRLF +
'Content-Disposition: form-data; name=' + AnsiQuotedStr(InputText2FieldName, '"') + CRLF +
'Content-Type: text/plain' + CRLF +
CRLF);
WriteStrToStream(HTTP.Document, InputText2);
WriteStrToStream(HTTP.Document,
CRLF +
'--' + Bound + CRLF +
'Content-Disposition: form-data; name=' + AnsiQuotedStr(InputFileFieldName, '"') + ';' + CRLF +
#9'filename=' + AnsiQuotedStr(InputFileName, '"') + CRLF +
'Content-Type: application/octet-string' + CRLF +
CRLF);
HTTP.Document.CopyFrom(InputFileData, 0);
WriteStrToStream(HTTP.Document,
CRLF +
'--' + Bound + '--' + CRLF);
HTTP.MimeType := 'multipart/form-data; boundary=' + Bound;
Result := HTTP.HTTPMethod('POST', URL);
if Result then
ResultData.LoadFromStream(HTTP.Document);
finally
HTTP.Free;
end;
end;
If you switch to Indy, you can use its TIdMultipartFormDataStream
class:
function HttpPostFile(const URL, InputText1FieldName, InputText1, InputText2FieldName, InputText2, InputFileFieldName, InputFileName: string; InputFileData: TStream; ResultData: TStrings): Boolean;
var
HTTP: TIdHTTP;
Input: TIdMultipartFormDataStream;
Output: TMemoryStream;
begin
Result := False;
try
Output := TMemoryStream.Create;
try
HTTP := TIdHTTP.Create;
try
Input := TIdMultipartFormDataStream.Create;
try
Input.AddFormField(InputText1FieldName, InputText1);
Input.AddFormField(InputText2FieldName, InputText2);
Input.AddFormField(InputFileFieldName, 'application/octet-stream', '', InputFileData, InputFileName);
HTTP.Post(URL, Input, Output);
finally
Input.Free;
end;
finally
HTTP.Free;
end;
Output.Position := 0;
ResultData.LoadFromStream(Output);
Result := True;
finally
Output.Free;
end;
except
end;
end;