bash: debug option and functions

Question

If I run

bash -x myscript.sh

I'll get debugging output.

But if I have a function in myscript.sh, the code in the function is immune to -x option. It writes to output only the name of the function.

How to obtain debugging output for functions in bash scripts?

Update:

Following the ztank1013's response, I just realized that I used ksh, not bash. Seems bash has by default the functrace option enabled in my system(thanks bash-o-logist)

I am satisfied, but for the community I maintain the question open for ksh.

For script:

#!/bin/ksh

a=2
testering(){
        a=3
        if [ $a -eq 3 ]; then
                echo lili
        fi
}
if [ $a -eq 2 ]; then
        echo mimi
fi

testering
exit

output of ksh -x ./testdebug.sh is:

+ a=2
+ [ 2 -eq 2 ]
+ echo mimi
mimi
+ testering
lili
+ exit

So, for ksh, what's the trick?

(If no answer will come, the 'correct' will go to bash-o-logist.)

Answer 1

With bash, you can use functrace option in your script

set -o functrace

See manpage for bash for other debugger options.