I have been using CUDA for a few weeks, but I have some doubts about the allocation of blocks/warps/thread. I am studying the architecture from a didactic point of view (university project), so reaching peak performance is not my concern.
First of all, I would like to understand if I got these facts straight:
The programmer writes a kernel, and organize its execution in a grid of thread blocks.
Each block is assigned to a Streaming Multiprocessor (SM). Once assigned it cannot migrate to another SM.
Each SM splits its own blocks into Warps (currently with a maximum size of 32 threads). All the threads in a warp executes concurrently on the resources of the SM.
The actual execution of a thread is performed by the CUDA Cores contained in the SM. There is no specific mapping between threads and cores.
If a warp contains 20 thread, but currently there are only 16 cores available, the warp will not run.
On the other hand if a block contains 48 threads, it will be split into 2 warps and they will execute in parallel provided that enough memory is available.
If a thread starts on a core, then it is stalled for memory access or for a long floating point operation, its execution could resume on a different core.
Are they correct?
Now, I have a GeForce 560 Ti so according to the specifications it is equipped with 8 SM, each containing 48 CUDA cores (384 cores in total).
My goal is to make sure that every core of the architecture executes the SAME instructions. Assuming that my code will not require more register than the ones available in each SM, I imagined different approaches:
I create 8 blocks of 48 threads each, so that each SM has 1 block to execute. In this case will the 48 threads execute in parallel in the SM (exploiting all the 48 cores available for them)?
Is there any difference if I launch 64 blocks of 6 threads? (Assuming that they will be mapped evenly among the SMs)
If I "submerge" the GPU in scheduled work (creating 1024 blocks of 1024 thread each, for example) is it reasonable to assume that all the cores will be used at a certain point, and will perform the same computations (assuming that the threads never stall)?
Is there any way to check these situations using the profiler?
Is there any reference for this stuff? I read the CUDA Programming guide and the chapters dedicated to hardware architecture in "Programming Massively Parallel Processors" and "CUDA Application design and development"; but I could not get a precise answer.
Two of the best references are
I'll try to answer each of your questions.
The programmer divides work into threads, threads into thread blocks, and thread blocks into grids. The compute work distributor allocates thread blocks to Streaming Multiprocessors (SMs). Once a thread block is distributed to a SM the resources for the thread block are allocated (warps and shared memory) and threads are divided into groups of 32 threads called warps. Once a warp is allocated it is called an active warp. The two warp schedulers pick two active warps per cycle and dispatch warps to execution units. For more details on execution units and instruction dispatch see 1 p.7-10 and 2.
4'. There is a mapping between laneid (threads index in a warp) and a core.
5'. If a warp contains less than 32 threads it will in most cases be executed the same as if it has 32 threads. Warps can have less than 32 active threads for several reasons: number of threads per block is not divisible by 32, the program execute a divergent block so threads that did not take the current path are marked inactive, or a thread in the warp exited.
6'. A thread block will be divided into WarpsPerBlock = (ThreadsPerBlock + WarpSize - 1) / WarpSize There is no requirement for the warp schedulers to select two warps from the same thread block.
7'. An execution unit will not stall on a memory operation. If a resource is not available when an instruction is ready to be dispatched the instruction will be dispatched again in the future when the resource is available. Warps can stall at barriers, on memory operations, texture operations, data dependencies, ... A stalled warp is ineligible to be selected by the warp scheduler. On Fermi it is useful to have at least 2 eligible warps per cycle so that the warp scheduler can issue an instruction.
See reference 2 for differences between a GTX480 and GTX560.
If you read the reference material (few minutes) I think you will find that your goal does not make sense. I'll try to respond to your points.
1'. If you launch kernel<<<8, 48>>> you will get 8 blocks each with 2 warps of 32 and 16 threads. There is no guarantee that these 8 blocks will be assigned to different SMs. If 2 blocks are allocated to a SM then it is possible that each warp scheduler can select a warp and execute the warp. You will only use 32 of the 48 cores.
2'. There is a big difference between 8 blocks of 48 threads and 64 blocks of 6 threads. Let's assume that your kernel has no divergence and each thread executes 10 instructions.
In order to get optimal efficiency the division of work should be in multiples of 32 threads. The hardware will not coalesce threads from different warps.
3'. A GTX560 can have 8 SM * 8 blocks = 64 blocks at a time or 8 SM * 48 warps = 512 warps if the kernel does not max out registers or shared memory. At any given time on a portion of the work will be active on SMs. Each SM has multiple execution units (more than CUDA cores). Which resources are in use at any given time is dependent on the warp schedulers and instruction mix of the application. If you don't do TEX operations then the TEX units will be idle. If you don't do a special floating point operation the SUFU units will idle.
4'. Parallel Nsight and the Visual Profiler show
a. executed IPC
b. issued IPC
c. active warps per active cycle
d. eligible warps per active cycle (Nsight only)
e. warp stall reasons (Nsight only)
f. active threads per instruction executed
The profiler do not show the utilization percentage of any of the execution units. For GTX560 a rough estimate would be IssuedIPC / MaxIPC. For MaxIPC assume GF100 (GTX480) is 2 GF10x (GTX560) is 4 but target is 3 is a better target.