I'm stuck with this problem:
I have a div (#container) which contains two divs. The height of the container should be exact 100%, regardless of the content of this div - not less not more.
Inside this div I want two full-width divs on top of each other:
Currently I have the following css ...
body {
margin:0;
padding:0;
}
#container
{
position: relative;
width: 500px;
height: 100%;
max-height: 100%;
background-color: #f00;
}
#upper {
width: 100%;
background-color: #0f0;
}
#lower {
width: 100%;
background-color: #00f;
overflow: auto;
}
... as well as this code:
<div id="container">
<div id="upper"></div>
<div id="lower"></div>
</div>
How can the (#container)'s height be exactly 100% - independent of its content? Now the height becomes larger because of the combined content of (#upper) and (#lower)?
How can (#lower) be scrollable (only up and down, not left to right!)?
Thank you very much for your feedback, I hope we can all learn from this.
You should set your html
and body
elements to have a height of 100%, so your children divs know what to base the percentage off of. Like so:
html, body {
height:100%;
width:100%;
}
Change your container to this:
#container
{
width: 500px;
height: 100%;
background-color: #f00;
}
As for your scrolling issue, you're almost there. Change the code to the following:
#lower {
width: 100%;
height:100px;
background-color: #00f;
overflow-y: auto;
}
For it to work best, have a fixed height set on your lower div and that'll make it easy for the scrollable action to work best.
EDIT:
I realized I mis-read your question. You'd like to have your lower div fill the remaining height of the window. Here's how to do that in jquery:
var top = $('#upper').height();
var remaining_height = parseInt($(window).height() - top);
$('#lower').height(remaining_height);
I still haven't found a way to do that with only CSS... Sadly.