I have a div element wrapping other div elements like so:
<div style="overflow:hidden">
<div id="a"></div>
<div id="b"></div>
</div>
I have other css rules that manage the dimensions of the outer div. In my actual code, I want to position the div#a exactly 10 px below the outer div. However, I want div#b to still be cut off by the outer div's overflow:hidden.
What is the best way to achieve this?
Method 1
A good way to do it is by setting the overflowing element to position:fixed
(which will make it ignore the parent overflow), and then positioning it relative to the parent using this technique:
.parent {
position: relative;
.fixed-wrapper {
position: absolute;
.fixed {
position: fixed;
}
}
}
One caveat is that you cannot have any of the top,right,left,bottom properties set on the fixed element (they must all be default 'auto'). If you need to adjust the position slightly, you can do so using positive/negative margins instead.
Method 2
Another trick I recently discovered is to keep the overflow:hidden
element with position:static
and position the overriding element relative to a higher parent (rather than the overflow:hidden
parent). Like so: