Swap two bits with a single operation in C?

Question

Let's say I have a byte with six unknown values:

???1?0??

and I want to swap bits 2 and 4 (without changing any of the ? values):

???0?1??

But how would I do this in one operation in C?

I'm performing this operation thousands of times per second on a microcontroller so performance is the top priority.

It would be fine to "toggle" these bits. Even though this is not the same as swapping the bits, toggling would work fine for my purposes.

Answer 1

Try:

x ^= 0x14;

That toggles both bits. It's a little bit unclear in question as you first mention swap and then give a toggle example. Anyway, to swap the bits:

x = precomputed_lookup [x];

where precomputed_lookup is a 256 byte array, could be the fastest way, it depends on the memory speed relative to the processor speed. Otherwise, it's:

x = (x & ~0x14) | ((x & 0x10) >> 2) | ((x & 0x04) << 2);

EDIT: Some more information about toggling bits.

When you xor (^) two integer values together, the xor is performed at the bit level, like this:

for each (bit in value 1 and value 2)
   result bit = value 1 bit xor value 2 bit

so that bit 0 of the first value is xor'ed with bit 0 of the second value, bit 1 with bit 1 and so on. The xor operation doesn't affect the other bits in the value. In effect, it's a parallel bit xor on many bits.

Looking at the truth table for xor, you will see that xor'ing a bit with the value '1' effectively toggles the bit.

 a  b a^b
 0  0  0
 0  1  1
 1  0  1
 1  1  0

So, to toggle bits 1 and 3, write a binary number with a one where you want the bit to toggle and a zero where you want to leave the value unchanged:

00001010

convert to hex: 0x0a. You can toggle as many bits as you want:

0x39 = 00111001

will toggle bits 0, 3, 4 and 5