I'm attempting to learn C and already I've run into an issue. I assume its trivial but I need to know it. I have written:
#include <stdio.h>
#include <string.h>
int main()
{
char str_a[20];
strcpy(str_a, "Hello, world!\n");
printf(str_a);
}
Once I attempt to compile it with: gcc -g -o char_array2 char_array2.c I receive an error saying:
char_array2.c: In function ‘main’:
char_array2.c:9:2: warning: format not a string literal and no format arguments [-Wformat-security]
Can anyone help please?
When using printf
, the format string is better be a string literal and not a variable:
printf("%s", str_a);