executing a process with argc=0

c integer-overflow argv argc
Keeto picture Keeto · Nov 13, 2011 · Viewed 8.6k times · Source

Is it possible to execute a process whose argc = 0? I need to execute a program but it is extremely important for its argc to be equal to 0. Is there a way to do that? I tried to put 2^32 arguments in the command line so that it appears as if argc = 0 but there is a maximum limit to the number of arguments.

Answer

ibid picture ibid · Nov 13, 2011

You can write a program that calls exec directly; that allows you to specify the command-line arguments (including the program name) and lack thereof.

Related questions

How do I detect unsigned integer multiply overflow?

I was writing a program in C++ to find all solutions of ab = c, where a, b and c together use all the digits 0-9 exactly once. The program looped over values of a and b, and it ran a …

Read More
How to check for signed integer overflow in C without undefined behaviour?

There's (1): // assume x,y are non-negative if(x > max - y) error; And (2): // assume x,y are non-negative int sum = x + y; if(sum < x || sum < y) error; Whichs is preferred or is there a better way.

Read More
Catch and compute overflow during multiplication of two large integers

I am looking for an efficient (optionally standard, elegant and easy to implement) solution to multiply relatively large numbers, and store the result into one or several integers : Let say I have two 64 bits integers declared like this : uint64_t …

Read More