Hide GCC warning "set but not used"?

c gcc warnings hide
jean picture jean · Nov 9, 2011 · Viewed 11.6k times · Source

I want to do a function to get a pointer on a struct. I done this : 

void *getTokenList() {
    static t_token *list;

    return &list;
}

At compilation, I have this warning : warning: variable ‘list’ set but not used [-Wunused-but-set-variable]

Is it possible to disable this warning for this function (only this one), or put an GCC attribute on this variable to hide this warning?

I had put #pragma GCC diagnostic ignored "-Wunused-but-set-variable" in top of my file but I want to hide this warning ONLY for this variable in this function.

Thanks, Jean

Answer

cnicutar picture cnicutar · Nov 9, 2011

You can use this to shut it off:

(void)list;

Alternatively and less portably you can use __attribute__((unused)).

Related questions

Why do I get a warning every time I use malloc?

If I use malloc in my code: int *x = malloc(sizeof(int)); I get this warning from gcc: new.c:7: warning: implicit declaration of function ‘malloc’ new.c:7: warning: incompatible implicit declaration of built-in function ‘malloc’

Read More
Disable warning: the `gets' function is dangerous in GCC through header files?

I am using the function gets() in my C code. My code is working fine but I am getting a warning message (.text+0xe6): warning: the `gets' function is dangerous and should not be used. I want this warning message …

Read More
How to remove the warning in gcc 4.6: missing initializer [-Wmissing-field-initializers]?

The code: GValue value = { 0 }; Give the following warning: missing initializer [-Wmissing-field-initializers] I know that's a gcc's BUG; but is there some trick to remove it? really not nice see such unreal warnings. But I don't want power off the warning …

Read More