How to printf long long

Question

I'm doing a program that aproximate PI and i'm trying to use long long, but it isn't working. Here is the code

#include<stdio.h>
#include<math.h>
typedef long long num;
main(){
    num pi;
    pi=0;
    num e, n;
    scanf("%d", &n);
    for(e=0; 1;e++){
      pi += ((pow((-1.0),e))/(2.0*e+1.0));
      if(e%n==0)
        printf("%15lld -> %1.16lld\n",e, 4*pi);
      //printf("%lld\n",4*pi);
    }
}

Answer 1

%lld is the standard C99 way, but that doesn't work on the compiler that I'm using (mingw32-gcc v4.6.0). The way to do it on this compiler is: %I64d

So try this:

if(e%n==0)printf("%15I64d -> %1.16I64d\n",e, 4*pi);

and

scanf("%I64d", &n);

The only way I know of for doing this in a completely portable way is to use the defines in <inttypes.h>.

In your case, it would look like this:

scanf("%"SCNd64"", &n);
//...    
if(e%n==0)printf("%15"PRId64" -> %1.16"PRId64"\n",e, 4*pi);

It really is very ugly... but at least it is portable.