I'm going to ask something about my code provided below... My question is in the line where there's a comment /*This line*/
. I used variable y and x: y for the HEIGHT and x for the WIDTH. The very first time I run the program, the code was scanf("%d,%d", &y, &x);
but unfortunately, the program was not running properly. But when I modified the code with this scanf("%d,%d", &x, &y);
, then, I was able to run the program in turn. I can't understand how it happened, since I had set the y as HEIGHT and x as WIDTH?
File Edit Run Compile Project Options Debug Break/watch
╒════════════════════════════════════ Edit ════════════════════════════════════╕
│ Line 1 Col 43 Insert Indent Tab Fill Unindent * C:NONAME.C │
│#define HEIGHT 5 │
│#define WIDTH 10 │
│ │
│char enemy[HEIGHT][WIDTH]= │
│ { {0,0,0,0,0,0,0,0,0,0}, │
│ {0,1,1,0,0,1,0,0,0,0}, │
│ {0,0,0,1,0,1,0,1,1,0}, │
│ {0,0,0,0,0,0,0,0,1,1}, │
│ {0,0,1,1,0,1,0,0,0,1} }; │
│ │
│main() │
│{ │
│ char friend[HEIGHT][WIDTH]; │
│ int x,y; │
│ │
│ clrscr(); │
│ │
│ for(y=0; y<HEIGHT; y++) |
| for(x=0; x<WIDTH; x++) |
| friend[y][x]='.'; |
| |
| while(x >= 0) |
| { |
| for(y=0; y<HEIGHT; y++) |
| { |
| for(x=0; x<WIDTH; x++) |
| printf("%c", friend[y][x]); |
| printf("\n"); |
| } |
| |
| printf("Coordinates: "); |
| scanf("%d,%d", &x, &y); /*This line*/ |
| |
| if(enemy[y][x] == 1) |
| friend[y][x]="\xDB"; |
| else |
| friend[y][x]="\xB0"; |
| } |
|} │
├─────────────────────────────────── Watch ────────────────────────────────────┤
│ │
└──────────────────────────────────────────────────────────────────────────────┘
F1-Help F5-Zoom F6-Switch F7-Trace F8-Step F9-Make F10-Menu NUM
The problem is the input data. 5,2 meant row 5, column 2, and the problem is that row 5 does not exist (Height is 5, so you have rows from 0 to 4). As soon as you changed the values, they became 2, 5, which correctly point to row 2 (third row) and column 5 (sixth column).