The below fails to compile:
typedef int arr[10];
int main(void) {
return sizeof arr;
}
sizeof.c:3: error: expected expression before ‘arr’
but if I change it to
sizeof(arr);
everything is fine. Why?
According to 6.5.3, there are two forms for sizeof
as the following:
sizeof unary-expression
sizeof ( type-name )
Since arr
in your code is a type-name
, it has to be parenthesized.