Under what situation is it possible for GCC to not throw an "undefined reference" link error message when trying to call made-up functions?
For example, a situation in which this C code is compiled and linked by GCC:
void function()
{
made_up_function_name();
return;
}
...even though made_up_function_name
is not present anywhere in the code (not headers, source files, declarations, nor any third party library).
Can that kind of code be accepted and compiled by GCC under certain conditions, without touching the actual code? If so, which?
Thanks.
EDIT: no previous declarations or mentions to made_up_function_name
are present anywhere else. Meaning that a grep -R
of the whole filesystem will only show that exact single line of code.
Yes, it is possible to avoid reporting undefined references - using --unresolved-symbols
linker option.
g++ mm.cpp -Wl,--unresolved-symbols=ignore-in-object-files
From man ld
--unresolved-symbols=method
Determine how to handle unresolved symbols. There are four possible values for method:
ignore-all Do not report any unresolved symbols. report-all Report all unresolved symbols. This is the default. ignore-in-object-files Report unresolved symbols that are contained in shared libraries, but ignore them if they come from regular object files. ignore-in-shared-libs Report unresolved symbols that come from regular object files, but ignore them if they come from shared libraries. This can be useful when creating a dynamic binary and it is known that all the shared libraries that it should be referencing are included on the linker's command line.
The behaviour for shared libraries on their own can also be controlled by the --[no-]allow-shlib-undefined option.
Normally the linker will generate an error message for each reported unresolved symbol but the option --warn-unresolved-symbols can change this to a warning.