I have to define a 24-bit data type.I am using char[3]
to represent the type. Can I typedef char[3]
to type24
? I tried it in a code sample. I put typedef char[3] type24;
in my header file. The compiler did not complain about it. But when I defined a function void foo(type24 val) {}
in my C file, it did complain. I would like to be able to define functions like type24_to_int32(type24 val)
instead of type24_to_int32(char value[3])
.
The typedef would be
typedef char type24[3];
However, this is probably a very bad idea, because the resulting type is an array type, but users of it won't see that it's an array type. If used as a function argument, it will be passed by reference, not by value, and the sizeof
for it will then be wrong.
A better solution would be
typedef struct type24 { char x[3]; } type24;
You probably also want to be using unsigned char
instead of char
, since the latter has implementation-defined signedness.