error C4996: 'scanf': This function or variable may be unsafe in c programming

Question

I have created a small application to find max number by using user-defined function with parameter. When I run it, it shows this message

Error 1 error C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details.

What do I do to resolve this?

This is my code

#include<stdio.h>

void findtwonumber(void);
void findthreenumber(void);

int main() {
    int n;
    printf("Fine Maximum of two number\n");
    printf("Fine Maximum of three number\n");

    printf("Choose one:");
    scanf("%d", &n);
    if (n == 1)
    {
        findtwonumber();
    }
    else if (n == 2)
    {
        findthreenumber();
    }
    return 0;
}

void findtwonumber(void)
{
    int a, b, max;
    printf("Enter a:");
    scanf("%d", &a);
    printf("Enter b:");
    scanf("%d", &b);
    if (a>b)
        max = a;
    else
        max = b;
    printf("The max is=%d", max);
}

void findthreenumber(void)
{
    int a, b, c, max;
    printf("Enter a:");
    scanf("%d", &a);
    printf("Enter b:");
    scanf("%d", &b);
    printf("Enter c:");
    scanf("%d", &c);
    if (a>b)
        max = a;
    else if (b>c)
        max = b;
    else if (c>a)
        max = c;
    printf("The max is=%d", max);
}

Answer 1

It sounds like it's just a compiler warning.

Usage of scanf_s prevents possible buffer overflow.
See: http://code.wikia.com/wiki/Scanf_s

Good explanation as to why scanf can be dangerous: Disadvantages of scanf

So as suggested, you can try replacing scanf with scanf_s or disable the compiler warning.