Store argv to an int array

Question

I have code like this to store argv to a dynamically allocated int array:

int *data;    // pointer to array of integer numbers
int size;     // size of data array

int main(int argc, char* argv[]) {
  // initialize array data
  size=argc;
  printf("%dSize=\n",size);
  printf("%d\n",argc);
  data=(int*)calloc(size,sizeof(int));
  int i=0;
  for (i=1;i<size;i++)
  {
   data[i]=argv[i];
   printf("%d\n",data[i]);
  }
  for (i=1;i<argc;i++)
  {
   printf("%d\n",argv[i]);
  }
  return 0;
}

When I run in command line: ./sumprime 5 1 2 3 4 It prints:

6Size=
6
15311660
15311662
15311664
15311666
15311668
15311660
15311662
15311664
15311666
15311668

Not an array of 5 1 2 3 4 as I expected. How can I store an int array from argv and then print it out?

Answer 1

Should be:

   data[i]=atoi(argv[i]);

Remember command line argument are strings. So even though you pass an integer in the command line its a string that needs to be converted to an integer.