How to ignore/remove leading zeros?

Question

I am writing a program to add two large numbers in C. My integer array result holds the sum of the two numbers (which were also stored in arrays).

For example, if the result array is [0,0,3,2] (actual array size is 20)

If 32 is my actual result, how can I display the contents of the result array without the leading zeros ?

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define BASE 10
void align(int A[],int n);
void add(int A[],int B[], int C[]);
void Invert(int* a, int n);

int main(int argc, char** argv){
    char input1[20];
    char input2[20];
    int size = 20;
    int a;
    int b;
    int num1[20];
    int num2[20];
    int result[20];
    int length1 = strlen(argv[1]);
    int length2 = strlen(argv[2]);
    int i = 0;
    for (i=0;i<length1;i++){
       input1[i] = argv[1][i];
    }
    for (i=0;i<length2;i++){
        input2[i] = argv[2][i];
    }

    a=atoi(input1);
    b=atoi(input2);
    align(num1,a);
    align(num2,b);
    add(num1,num2,result);
    Invert(result,size);
    for (i=0;i<20;i++){
        printf("%d",result[i]);
    }

    return 0;
}

void align (int A[], int n){
    int i = 0;

    while (n) {
        A[i++] = n % BASE;

        n /= BASE;
    }

    while (i < 20) A[i++] = 0;
}

void add (int A[], int B[], int C[]) {
    int i, carry, sum;
    carry = 0;
    for (i=0; i<20; i++) {
        sum = A[i] + B[i] + carry;
        if (sum >= BASE) {
            carry = 1;
            sum -= BASE;
        } else
            carry = 0;
        C[i] = sum;
    }

    if (carry) printf ("overflow in addition!\n");
}

void Invert(int* a, int n)
{
    int i;
    int b;
    for(i=0; i<n/2; i++){
        b = a[i];
        a[i] = a[n-i-1];
        a[n-i-1] = b;
    } 
}

`

Answer 1

To get the actual digits (I assume that each digit is stored as a byte in an array of 20 bytes, lowest digit at highest index), you do something like this:

int i;
int size = sizeof(thearray) / sizeof(thearray[0]);

/* find first non-0 byte, starting at the highest "digit" */
for (i = 0; i < size - 1; ++i)
    if (thearray[i] != 0)
        break;

/* output every byte as character */
for (; i < size; i++)
    printf("%c", thearray[i] + '0'); /* 0 --> '0', 1 --> '1', etc. */
printf("\n");