End of line character / Carriage return

c file text carriage-return end-of-line
mrtgnccn picture mrtgnccn · May 21, 2014 · Viewed 12.3k times · Source

I'm reading a normal text file and write all the words as numbers to another text. When a line finishes it looks for a "new line character (\n)" and continues from the new line. In Ubuntu it executes perfectly but in Windows (DevC++) it cannot operate the function. My problem is the text in Windows which I read haven't got new line characters. Even I put new lines by my hand my program cannot see it. When I want to print the character at the end of the line, it says it is a space (ascii = 32) and I am sur that I am end of the line. Here is my end of line control code, what can I do to fix it? And I read about a character called "carriage return (\r)" but it doesn't fix my problem either.

c = fgetc(fp);
printf("%d", c);
fseek(fp, -1, SEEK_SET);
if(c == '\n' || c == '\r')
    fprintf(fp3, "%c%c", '\r', '\n');

Answer

Ryan Haining picture Ryan Haining · May 21, 2014

If you are opening a text file and want newline conversions to take place, open the file in "r" mode instead of "rb"

FILE *fp = fopen(fname, "r");

this will open in text mode instead of binary mode, which is what you want for text files. On linux there won't appear to be a difference, but on windows, \r\n will be translated to \n

A possible solution it seems, is to read the numbers out of your file into an int variable directly.

int n;
fscanf(fp, "%d", &n);

unless the newline means something significant to you.

Related questions

How to compare an ASCII value

I want to store the ASCII value of a letter into a variable, how can I do this? for example : r ASCII variable = 82 main() { character = "character read from a file"; variable= "r ascii"; //(in this case 82), the problem is that …

Read More
In C, how to print out a txt file line by line?

int main() { FILE *infile; FILE *infile2; char input[255],input2[255]; int status1, status2; infile = fopen("test.txt", "r"); infile2 = fopen("test2.txt", "r"); if(infile == NULL) { printf("Can not open file 1!\n"); } else if(infile2 == NULL) { printf("Can not open file 2!\…

Read More
How can I get the list of files in a directory using C or C++?

How can I determine the list of files in a directory from inside my C or C++ code? I'm not allowed to execute the ls command and parse the results from within my program.

Read More