Can't catch apostrophe in if statement

Question

I am creating a program that takes a text file, and a word. It reads a text file and compares the word to the current word being read. The way I built it was to ignore the "'s". For example if I am searching "NASA" and I came across the word "NASA's", it would just read it as "NASA". Unfortunately I can't catch the apostrophe by using "if (ch == ''\')", "ch" being the current char. I reason being maybe because the apostrophes in the text file look like this ’. I don't know how to accommodate for that.

Here's what I have to catch an apostrophe:

else if (ch == '\'')
                {

#if 1           
                    printf("Comparing Apostrophe\n");
#endif
                    continue;

                }

Please note that it is part of a bigger program, which I am not allowed to show you. This explains the "else if" ion the beginning.

Thanks.

Answer 1

If your apostrophes look like '’', then you should just check for the '’' character, it won't do that for you. That's a different character - looks like extended ASCII character 146 (decimal), "right single quotation mark". The text probably came from MS Office - it loves to convert single and double quotes into single and double so-called "smart" quotes (which, if you're doing anything with the text outside of Office, are anything but.) And as has been pointed out, the "left single quotation mark", ascii character 145, is the other half of that same set, so there might be some of those in your text as well. I.e.:

else if (ch == '\'' || ch == '’' || ch == '‘')
{
    [do stuff]
}