How do you escape the % sign when using printf
in C?
printf("hello\%"); /* not like this */
You can escape it by posting a double '%' like this: %%
Using your example:
printf("hello%%");
Escaping '%' sign is only for printf. If you do:
char a[5];
strcpy(a, "%%");
printf("This is a's value: %s\n", a);
It will print: This is a's value: %%