This is more of a curious query than an important question, but why when printing hex as an 8 digit number with leading zeros, does this %#08X Not display the same result as 0x%08X?
When I try to use the former, the 08 formatting flag is removed, and it doesn't work with just 8.
Again I was just curious.
Answer
The # part gives you a 0x in the output string. The 0 and the x count against your "8" characters listed in the 08 part. You need to ask for 10 characters if you want it to be the same.
int i = 7;
printf("%#010x\n", i); // gives 0x00000007
printf("0x%08x\n", i); // gives 0x00000007
printf("%#08x\n", i); // gives 0x000007
Also changing the case of x, affects the casing of the outputted characters.
printf("%04x", 4779); // gives 12ab
printf("%04X", 4779); // gives 12AB