Why is sizeof considered an operator?

c operators sizeof
Arpit picture Arpit · Sep 8, 2009 · Viewed 22.7k times · Source

Why is sizeof considered an operator and not a function?

What property is necessary to qualify as an operator?

Answer

Steve Jessop picture Steve Jessop · Sep 8, 2009

Because the C standard says so, and it gets the only vote.

As consequences:

  • The operand of sizeof can be a parenthesised type, sizeof (int), instead of an object expression.
  • The parentheses are unnecessary: int a; printf("%d\n", sizeof a); is perfectly fine. They're often seen, firstly because they're needed as part of a type cast expression, and secondly because sizeof has very high precedence, so sizeof a + b isn't the same as sizeof (a+b). But they aren't part of the invocation of sizeof, they're part of the operand.
  • You can't take the address of sizeof.
  • The expression which is the operand of sizeof is not evaluated at runtime (sizeof a++ does not modify a).
  • The expression which is the operand of sizeof can have any type except void, or function types. Indeed, that's kind of the point of sizeof.

A function would differ on all those points. There are probably other differences between a function and a unary operator, but I think that's enough to show why sizeof could not be a function even if there was a reason to want it to be.

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