How to get size of 2D array pointed by a double pointer?

Question

I am trying to get the number of rows and columns of a 2D Array from a double pointer pointed to the array.

#include <stdio.h>
#include <stdlib.h>

void get_details(int **a)
{
 int row =  ???     // how get no. of rows
 int column = ???  //  how get no. of columns
 printf("\n\n%d - %d", row,column);
}

Above function needs to print the details of the size, where am going wrong.

int main(int argc, char *argv[])
{
 int n = atoi(argv[1]),i,j;
 int **a =(int **)malloc(n*sizeof(int *)); // using a double pointer
 for(i=0;i<n;i++)
   a[i] = (int *)malloc(n*sizeof(int));
 printf("\nEnter %d Elements",n*n);
 for(i=0;i<n;i++)
  for(j=0;j<n;j++)
  {
   printf("\nEnter Element %dx%d : ",i,j);
   scanf("%d",&a[i][j]);
  }
 get_details(a);
 return 0;
 }

I am using malloc to create the array.

---

What if I use something like this

column = sizeof(a)/sizeof(int) ?

Answer 1

C doesn't do reflection.

Pointers don't store any metadata to indicate the size of the area they point to; if all you have is the pointer, then there's no (portable) way to retrieve the number of rows or columns in the array.

You will either need to pass that information along with the pointer, or you will need to use a sentinel value in the array itself (similar to how C strings use a 0 terminator, although that only gives you the logical size of the string, which may be smaller than the physical size of the array it occupies).

In The Development of the C Programming Language, Dennis Ritchie explains that he wanted aggregate types like arrays and structs to not just represent abstract types, but to represent the collection of bits that would occupy memory or disk space; hence, no metadata within the type. That's information you're expected to track yourself.