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C Macro definition to determine big endian or little endian machine?
int main()
{
int x = 1;
char *y = (char*)&x;
printf("%c\n",*y+48);
}
If it's little endian it will print 1. If it's big endian it will print 0. Is that correct? Or will setting a char* to int x always point to the least significant bit, regardless of endianness?
In short, yes.
Suppose we are on a 32-bit machine.
If it is little endian, the x
in the memory will be something like:
higher memory
----->
+----+----+----+----+
|0x01|0x00|0x00|0x00|
+----+----+----+----+
A
|
&x
so (char*)(&x) == 1
, and *y+48 == '1'
.
If it is big endian, it will be:
+----+----+----+----+
|0x00|0x00|0x00|0x01|
+----+----+----+----+
A
|
&x
so this one will be '0'
.