Say I have a struct defined as follows
struct my_struct
{
int num;
};
....
Here I have a pointer to my_struct
and I want to do an increment on num
void foo(struct my_struct* my_ptr)
{
// increment num
// method #1
my_ptr->num++;
// method #2
++(my_ptr->num);
// method #3
my_ptr->++num;
}
Do these 3 ways of incrementing num
do the same thing?
While we're at it, is it true that pre-increment is more efficient than post-increment?
Thanks!
First two will have the same effect (when on a line on their own like that), but the third method isn't valid C code (you can't put the ++
there).
As for efficiency, there is no difference. The difference you may have heard people talking about is when, in C++, you increment a non-pointer data type, such as an iterator. In some cases, pre-increment can be faster there.
You can see the generated code using GCC Explorer.
void foo(struct my_struct* my_ptr)
{
my_ptr->num++;
}
void bar(struct my_struct* my_ptr)
{
++(my_ptr->num);
}
Output:
foo(my_struct*): # @foo(my_struct*)
incl (%rdi)
ret
bar(my_struct*): # @bar(my_struct*)
incl (%rdi)
ret
As you can see, there's no difference whatsoever.
The only possible difference between the first two is when you use them in expressions:
my_ptr->num = 0;
int x = my_ptr->num++; // x = 0
my_ptr->num = 0;
int y = ++my_ptr->num; // y = 1