How are the specifiers %p and %Fp working in the following code?
void main()
{
int i=85;
printf("%p %Fp",i,i);
getch();
}
I am getting the o/p as 0000000000000055 0000000000000055
Answer
If this is what you are asking, %p and %Fp print out a pointer, specifically the address to which the pointer refers, and since it is printing out a part of your computer's architecture, it does so in Hexadecimal.
In C, you can cast between a pointer and an int, since a pointer is just a 32-bit or 64-bit number (depending on machine architecture) referring to the aforementioned chunk of memory.
And of course, 55 in hex is 85 in decimal.