USART receive interrupt stm32

Question

I develop on a map I'm working on STM32 and USART interrupts. After configuring the USART1 and make Enable receive interrupt. The problem that the interruption of reception have no detected????

Answer 1

Such a question is difficult to answer without knowing which specific processor you are using, which board you are using, and/or which compiler you are using. But in an attempt to be helpful, here's my code.

Here's my GPIO and NVIC initialization code using Sourcery CodeBench Lite with an STM32F4 processor mounted on a custom board.

GPIO_InitTypeDef GPIO_InitStructure;
NVIC_InitTypeDef NVIC_InitStructure;

GPIO_InitStructure.GPIO_OType = GPIO_OType_PP;
GPIO_InitStructure.GPIO_PuPd = GPIO_PuPd_UP;
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_AF;
GPIO_InitStructure.GPIO_Speed = GPIO_Speed_100MHz;

RCC_AHB1PeriphClockCmd(RCC_AHB1Periph_GPIOB, ENABLE);
RCC_APB1PeriphClockCmd(RCC_APB1Periph_USART3, ENABLE);

GPIO_PinAFConfig(GPIOB, GPIO_PinSource10, GPIO_AF_USART3);
GPIO_PinAFConfig(GPIOB, GPIO_PinSource11, GPIO_AF_USART3);  
GPIO_InitStructure.GPIO_Pin = GPIO_Pin_10 | GPIO_Pin_11;
GPIO_Init(GPIOB, &GPIO_InitStructure);

// Enable the USART RX Interrupt 
USART_ITConfig(USART3, USART_IT_RXNE, ENABLE);
NVIC_InitStructure.NVIC_IRQChannel = USART3_IRQn;
NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 0;
NVIC_InitStructure.NVIC_IRQChannelSubPriority = 0;
NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE;
NVIC_Init(&NVIC_InitStructure);

Of course your settings will vary depending on your processor, board and interrupt priority.

Here's my interrupt handler code. In my development environment, this handler is declared in my startup assembly file as a weak reference to Default_Handler...

Default_Handler:
b .  

/* ... */

.word     USART3_IRQHandler

/* ... */

.weak      USART3_IRQHandler      
.thumb_set USART3_IRQHandler,Default_Handler

... so as long as I provide a new declaration and implementation of this interrupt handler, the weak reference will be replaced. Here's what my code looks like.

//Interrupt handler declaration
void USART3_IRQHandler();

If you are using C++ you will need to declare it as follows:

//Interrupt handler declaration in C/C++
#ifdef __cplusplus
 extern "C" {
#endif
void USART3_IRQHandler();
#ifdef __cplusplus
 }
#endif

And here's the interrupt handler implemenation.

//Interrupt handler implementation
void USART3_IRQHandler()
{
    //handle interrupt
}