I'm dynamically calculating the size of an array. Something like:
void foo(size_t limit)
{
char buffer[limit * 14 + 1];
}
But just GCC compiler says:
error: ISO C90 forbids variable length array ‘buffer’
searching on SO I found this answer:
C99 §6.7.5.2:
If the size is an expression that is not an integer constant expression... ...each time it is evaluated it shall have a value greater than zero.
So, I did the re-declaration of size limit type variable to:
void foo(const size_t limit)
But it continues to give warning for me. Is this a GCC bug?
const
-qualifying a variable doesn't make it a compile-time constant (see C99 6.6 §6 for the defintion of an integer constant expression), and before the introduction of variable-length arrays with C99, array sizes needed to be compile-time constants.
It's rather obvious that const
-qualify a variable doesn't make it a compile-time constant, in particular in case of function parameters which won't be initialized until the function is called.
I see the following solutions to your problem:
-std=c99
or -std=gnu99
malloc()
alloca()
if available, which is the closest you can come to variable-length arrays with C90limit
argument overflowsAs a side note, even though C99 allows variable-length arrays, it's still illegal to use the value of an integer variable with static storage duration as size for an array with static storage duration, regardless of const
-qualification: While there's nothing which prevents this in principle if the integer variable is initialized in the same translation unit, you'd have to special-case variables with visible defintion from those whose definition resides in a different translation unit and would either have to disallow tentative defintions or require multiple compilation passes as the initialization value of a tentatively defined variable isn't known until the whole translation unit has been parsed.