How does the range-based for work for plain arrays?

Paul Manta picture Paul Manta · Oct 29, 2011 · Viewed 59.2k times · Source

In C++11 you can use a range-based for, which acts as the foreach of other languages. It works even with plain C arrays:

int numbers[] = { 1, 2, 3, 4, 5 };
for (int& n : numbers) {
    n *= 2;
}

How does it know when to stop? Does it only work with static arrays that have been declared in the same scope the for is used in? How would you use this for with dynamic arrays?

Answer

Johannes Schaub - litb picture Johannes Schaub - litb · Oct 29, 2011

It works for any expression whose type is an array. For example:

int (*arraypointer)[4] = new int[1][4]{{1, 2, 3, 4}};
for(int &n : *arraypointer)
  n *= 2;
delete [] arraypointer;

For a more detailed explanation, if the type of the expression passed to the right of : is an array type, then the loop iterates from ptr to ptr + size (ptr pointing to the first element of the array, size being the element count of the array).

This is in contrast to user defined types, which work by looking up begin and end as members if you pass a class object or (if there is no members called that way) non-member functions. Those functions will yield the begin and end iterators (pointing to directly after the last element and the begin of the sequence respectively).

This question clears up why that difference exists.