Resizing a C++ std::vector<char> without initializing data

Question

With vectors, one can assume that elements are stored contiguously in memory, allowing the range [&vec[0], &vec[vec.capacity()) to be used as a normal array. E.g.,

vector<char> buf;
buf.reserve(N);
int M = read(fd, &buf[0], N);

But now the vector doesn't know that it contains M bytes of data, added externally by read(). I know that vector::resize() sets the size, but it also clears the data, so it can't be used to update the size after the read() call.

Is there a trivial way to read data directly into vectors and update the size after? Yes, I know of the obvious workarounds like using a small array as a temporary read buffer, and using vector::insert() to append that to the end of the vector:

char tmp[N];
int M = read(fd, tmp, N);
buf.insert(buf.end(), tmp, tmp + M)

This works (and it's what I'm doing today), but it just bothers me that there is an extra copy operation there that would not be required if I could put the data directly into the vector.

So, is there a simple way to modify the vector size when data has been added externally?

Answer 1

vector<char> buf;
buf.reserve(N);
int M = read(fd, &buf[0], N);

This code fragment invokes undefined behavior. You can't write beyond than size() elements, even if you have reserved the space.

The correct code is like:

vector<char> buf;
buf.resize(N);
int M = read(fd, &buf[0], N);
buf.resize(M);

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PS. Your statement "With vectors, one can assume that elements are stored contiguously in memory, allowing the range [&vec[0], &vec[vec.capacity()) to be used as a normal array" isn't true. The allowable range is [&vec[0], &vec[vec.size()).