Bitmask switch statement

Question

I have this code in a section of my project:

enum myEnum
{
    invalid = -1,
    val1 = 1,
    val2 = 2,
    val3 = 4
};

int bitmask = val1 | val3;

if(bitmask & val1)
    ...
if(bitmask & val2)
    ...
if(bitmask & val3)
    ...

This is fine, and it works perfectly, but i've always wondered if it could be done with a switch. I was thinking something along the lines this:

int checkMask(int& mask)
{
    for(int i = 0; mask; mask &= ~(1 << i++))
    {
        if(mask & (1 << i))
        {
            int ret = mask & (1 << i);
            mask &= ~ret;
            return ret;
        }
    }

    return invalid;
}

#define START_BITMASK_SWITCH(x) int xcopy = x; while(xcopy) { switch(checkMask(xcopy))
#define END_BITMASK_SWITCH };

int bitmask = val1 | val3;

START_BITMASK_SWITCH(bitmask)
{
    case val1:
        ...
        break;
    case val2:
        ...
        break;
    case val3:
        ...
        break;
}
END_BITMASK_SWITCH

so my questions are:

have i just solved my problem? i suppose i have, but is it a clean solution?

is there a simpler way of accomplishing this?

is it a bad idea to mix #defines and functions?

Answer 1

No it's not a clean solution and for your context, you can avoid mixing #define and functions. You can try below solution, if you want switch():

int bitmask = val1 | val3;
int mask = 1;
while(bitmask)
{
  switch(bitmask & mask)
  {
  case val1: ... break;
  case val2: ... break;
  case val4: ... break;
  case val8: ... break;
  }
  bitmask &= ~mask; 
  mask <<= 1;
}