How do I link libcurl to my c++ program in linux?

Austin Witherspoon picture Austin Witherspoon · Jun 10, 2011 · Viewed 37.1k times · Source

I need to use libcurl in a piece of software I am writing on my ubuntu machine. I am using Eclipse to write and compile all of the software. When I put the libcurl files in the same folder as the .cpp file, and include the curl.h file in the header, When I attempt to compile the program, It comes up with these errors:

Building target: sms
Invoking: GCC C++ Linker
g++  -o"sms"  ./src/sms.o   
./src/sms.o: In function `main':
/home/geekman/workspace/sms/Debug/../src/sms.cpp:38: undefined reference to `curl_easy_init'
/home/geekman/workspace/sms/Debug/../src/sms.cpp:42: undefined reference to `curl_easy_setopt'
/home/geekman/workspace/sms/Debug/../src/sms.cpp:44: undefined reference to `curl_easy_setopt'
/home/geekman/workspace/sms/Debug/../src/sms.cpp:46: undefined reference to `curl_easy_perform'
/home/geekman/workspace/sms/Debug/../src/sms.cpp:47: undefined reference to `curl_easy_cleanup'
collect2: ld returned 1 exit status
make: *** [sms] Error 1

I took the contents of the include folder from libcurl, and placed them in the same folder as the .cpp file. then in the header of the .cpp file, I typed:

#include <curl/curl.h>

I also tried:

#include "curl/curl.h"

Any ideas on the problem? Thanks.

Answer

Adam Rosenfield picture Adam Rosenfield · Jun 10, 2011

Your header file inclusions are just fine; your problem is occurring at the linking step. In order to link against libcurl, you need to add the -lcurl command line option, assuming it's installed in a standard directory:

g++ -o sms ./src/sms.o -lcurl

If it's not installed in a standard directory, you also need to add the -L/path/to/libcurl, e.g. something like:

# Assuming that /home/geekman/workspace/libcurl is where libcurl.a is located
g++ -o sms ./src/sms.o -L/home/geekman/workspace/libcurl -lcurl

Also note that the -lcurl option has to appear after the list of object files you're linking, otherwise it won't link properly.