I am using a container to hold a list of pointers to anything:
struct Example {
std::vector<boost::any> elements;
}
To insert elements in this container, I had written a couple of helper functions (members of the struct Example
):
void add_any(boost::any& a) {
elements.push_back(a);
}
template<typename T>
void add_to_list(T& a) {
boost::any bany = &a;
add_any(bany);
}
Now, I would like to insert elements only when they are not present in this container. To do this, I thought that I would only need to call search
over elements
with an appropriate comparator function. However, I do not know how to compare the boost::any
instances.
My question:
Knowing that my boost::any
instances always contain a pointer to something; is it possible to compare two boost::any
values?
update
I thank you for your answers. I have also managed to do this in a probably unsafe way: using boost::unsafe_any_cast
to obtain a void**
and comparing the underlying pointer.
For the moment, this is working fine. I would, however, appreciate your comments: maybe this is a big mistake!
#include <boost/any.hpp>
#include <iostream>
#include <vector>
#include <string>
using namespace std;
bool any_compare(const boost::any& a1, const boost::any& a2) {
cout << "compare " << *boost::unsafe_any_cast<void*>(&a1)
<< " with: " << *boost::unsafe_any_cast<void*>(&a2);
return (*boost::unsafe_any_cast<void*>(&a1)) ==
(*boost::unsafe_any_cast<void*>(&a2));
}
struct A {};
class Example {
public:
Example() : elements(0),
m_1(3.14),
m_2(42),
m_3("hello"),
m_4() {};
virtual ~Example() {};
void test_insert() {
add_to_list(m_1);
add_to_list(m_2);
add_to_list(m_3);
add_to_list(m_4);
add_to_list(m_1); // should not insert
add_to_list(m_2); // should not insert
add_to_list(m_3); // should not insert
add_to_list(m_4); // should not insert
};
template <typename T>
void add_to_list(T& a) {
boost::any bany = &a;
add_any(bany);
}
private:
vector<boost::any> elements;
double m_1;
int m_2;
string m_3;
A m_4;
void add_any(const boost::any& a) {
cout << "Trying to insert " << (*boost::unsafe_any_cast<void*>(&a)) << endl;
vector<boost::any>::const_iterator it;
for (it = elements.begin();
it != elements.end();
++it) {
if ( any_compare(a,*it) ) {
cout << " : not inserting, already in list" << endl;
return;
}
cout << endl;
}
cout << "Inserting " << (*boost::unsafe_any_cast<void*>(&a)) << endl;
elements.push_back(a);
};
};
int main(int argc, char *argv[]) {
Example ex;
ex.test_insert();
unsigned char c;
ex.add_to_list(c);
ex.add_to_list(c); // should not insert
return 0;
}
You cannot directly provide it, but you can actually use any
as the underlying type... though for pointers it's pointless (ah!)
struct any {
std::type_info const& _info;
void* _address;
};
And a templated constructor:
template <typename T>
any::any(T* t):
_info(typeid(*t)),
_address(dynamic_cast<void*>(t))
{
}
This is, basically, boost::any
.
Now we need to "augment" it with our comparison mechanism.
In order to do so, we'll "capture" the implementation of std::less
.
typedef bool (*Comparer)(void*,void*);
template <typename T>
bool compare(void* lhs, void* rhs) const {
return std::less<T>()(*reinterpret_cast<T*>(lhs), *reinterpret_cast<T*>(rhs));
}
template <typename T>
Comparer make_comparer(T*) { return compare<T>; }
And augment the constructor of any
.
struct any {
std::type_info const& _info;
void* _address;
Comparer _comparer;
};
template <typename T>
any::any(T* t):
_info(typeid(*t)),
_address(dynamic_cast<void*>(t)),
_comparer(make_comparer(t))
{
}
Then, we provided a specialization of less
(or operator<
)
bool operator<(any const& lhs, any const& rhs) {
if (lhs._info.before(rhs._info)) { return true; }
if (rhs._info.before(lhs._info)) { return false; }
return (*lhs._comparer)(lhs._address, rhs._address);
}
Note: encapsulation, etc... are left as an exercise to the reader